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Convention-Python/Convention/Runtime/String.py

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from .Config import *
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def LimitStringLength(data, max_length:int=50) -> str:
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s:str = data if isinstance(data, str) else str(data)
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if len(s) <= max_length:
return s
else:
inside_str = "\n...\n...\n"
# 计算头尾部分的长度
head_length = max_length // 2
tail_length = max_length - head_length - len(inside_str) # 3 是省略号的长度
# 截取头尾部分并连接
return s[:head_length] + inside_str + s[-tail_length:]
def FillString(data:Any,
max_length: int = 50,
fill_char: str = " ",
side: Literal["left", "right", "center"] = "right"
) -> str:
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s:str = data if isinstance(data, str) else str(data)
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char = fill_char[0]
if len(s) >= max_length:
return s
else:
if side == "left":
return s + char * (max_length - len(s))
elif side == "right":
return char * (max_length - len(s)) + s
elif side == "center":
left = (max_length - len(s)) // 2
right = max_length - len(s) - left
return char * left + s + char * right
else:
raise ValueError(f"Unsupported side: {side}")
def Bytes2Strings(lines:List[bytes], encoding='utf-8') -> List[str]:
return [line.decode(encoding) for line in lines]
def Bytes2String(lines:List[bytes], encoding='utf-8') -> str:
return "".join(Bytes2Strings(lines, encoding))
def word_segmentation(
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sentence,
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cut_all: bool = False,
HMM: bool = True,
use_paddle: bool = False
) -> Sequence[Optional[Union[Any, str]]]:
try:
import jieba
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return jieba.dt.cut(str(sentence), cut_all=cut_all, HMM=HMM, use_paddle=use_paddle)
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except ImportError:
raise ValueError("jieba is not install")
def GetEditorDistanceAndOperations(s1:str, s2:str) -> Tuple[int, List[Tuple[str, int, int, str]]]:
"""
计算两个字符串的编辑距离和操作序列
操作格式: (操作类型, 开始位置, 结束位置, 内容)
位置基于源字符串s1
"""
m, n = len(s1), len(s2)
# 使用简单的LCS算法来找到最长公共子序列
# 然后基于LCS生成操作序列
lcs = [[0] * (n + 1) for _ in range(m + 1)]
# 构建LCS表
for i in range(1, m + 1):
for j in range(1, n + 1):
if s1[i - 1] == s2[j - 1]:
lcs[i][j] = lcs[i - 1][j - 1] + 1
else:
lcs[i][j] = max(lcs[i - 1][j], lcs[i][j - 1])
# 基于LCS生成操作序列
operations = []
i, j = m, n
while i > 0 or j > 0:
if i > 0 and j > 0 and s1[i - 1] == s2[j - 1]:
# 字符匹配,不需要操作
i -= 1
j -= 1
elif j > 0 and (i == 0 or lcs[i][j - 1] >= lcs[i - 1][j]):
# 需要插入s2[j-1]
# 找到插入位置在s1中的位置
insert_pos = i
operations.insert(0, ("add", insert_pos, insert_pos, s2[j - 1]))
j -= 1
else:
# 需要删除s1[i-1]
operations.insert(0, ("delete", i - 1, i, s1[i - 1]))
i -= 1
# 合并连续的操作
merged_operations = []
for op in operations:
if merged_operations and merged_operations[-1][0] == op[0]:
last_op = merged_operations[-1]
if op[0] == "add" and last_op[2] == op[1]:
# 合并连续的添加操作
merged_operations[-1] = (op[0], last_op[1], op[2], last_op[3] + op[3])
elif op[0] == "delete" and last_op[2] == op[1]:
# 合并连续的删除操作
merged_operations[-1] = (op[0], last_op[1], op[2], last_op[3] + op[3])
else:
merged_operations.append(op)
else:
merged_operations.append(op)
# 计算编辑距离
edit_distance = m + n - 2 * lcs[m][n]
return edit_distance, merged_operations