from .Config import * def LimitStringLength(data, max_length:int=50) -> str: s:str = data if isinstance(data, str) else str(data) if len(s) <= max_length: return s else: inside_str = "\n...\n...\n" # 计算头尾部分的长度 head_length = max_length // 2 tail_length = max_length - head_length - len(inside_str) # 3 是省略号的长度 # 截取头尾部分并连接 return s[:head_length] + inside_str + s[-tail_length:] def FillString(data:Any, max_length: int = 50, fill_char: str = " ", side: Literal["left", "right", "center"] = "right" ) -> str: s:str = data if isinstance(data, str) else str(data) char = fill_char[0] if len(s) >= max_length: return s else: if side == "left": return s + char * (max_length - len(s)) elif side == "right": return char * (max_length - len(s)) + s elif side == "center": left = (max_length - len(s)) // 2 right = max_length - len(s) - left return char * left + s + char * right else: raise ValueError(f"Unsupported side: {side}") def Bytes2Strings(lines:List[bytes], encoding='utf-8') -> List[str]: return [line.decode(encoding) for line in lines] def Bytes2String(lines:List[bytes], encoding='utf-8') -> str: return "".join(Bytes2Strings(lines, encoding)) def word_segmentation( sentence, cut_all: bool = False, HMM: bool = True, use_paddle: bool = False ) -> Sequence[Optional[Union[Any, str]]]: try: import jieba return jieba.dt.cut(str(sentence), cut_all=cut_all, HMM=HMM, use_paddle=use_paddle) except ImportError: raise ValueError("jieba is not install") def GetEditorDistanceAndOperations(s1:str, s2:str) -> Tuple[int, List[Tuple[str, int, int, str]]]: """ 计算两个字符串的编辑距离和操作序列 操作格式: (操作类型, 开始位置, 结束位置, 内容) 位置基于源字符串s1 """ m, n = len(s1), len(s2) # 使用简单的LCS算法来找到最长公共子序列 # 然后基于LCS生成操作序列 lcs = [[0] * (n + 1) for _ in range(m + 1)] # 构建LCS表 for i in range(1, m + 1): for j in range(1, n + 1): if s1[i - 1] == s2[j - 1]: lcs[i][j] = lcs[i - 1][j - 1] + 1 else: lcs[i][j] = max(lcs[i - 1][j], lcs[i][j - 1]) # 基于LCS生成操作序列 operations = [] i, j = m, n while i > 0 or j > 0: if i > 0 and j > 0 and s1[i - 1] == s2[j - 1]: # 字符匹配,不需要操作 i -= 1 j -= 1 elif j > 0 and (i == 0 or lcs[i][j - 1] >= lcs[i - 1][j]): # 需要插入s2[j-1] # 找到插入位置(在s1中的位置) insert_pos = i operations.insert(0, ("add", insert_pos, insert_pos, s2[j - 1])) j -= 1 else: # 需要删除s1[i-1] operations.insert(0, ("delete", i - 1, i, s1[i - 1])) i -= 1 # 合并连续的操作 merged_operations = [] for op in operations: if merged_operations and merged_operations[-1][0] == op[0]: last_op = merged_operations[-1] if op[0] == "add" and last_op[2] == op[1]: # 合并连续的添加操作 merged_operations[-1] = (op[0], last_op[1], op[2], last_op[3] + op[3]) elif op[0] == "delete" and last_op[2] == op[1]: # 合并连续的删除操作 merged_operations[-1] = (op[0], last_op[1], op[2], last_op[3] + op[3]) else: merged_operations.append(op) else: merged_operations.append(op) # 计算编辑距离 edit_distance = m + n - 2 * lcs[m][n] return edit_distance, merged_operations